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All valid points, however, we are not sure there is going to be enough volume to justify or to make back the upfront cost of development.
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Just a time sequence, is all, I believe.
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It has been too long, I know. Sorry. The devs are working hard on the next release. We think you will be pleased. Thank you for your patience.
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Argle wrote:Just FYI- According to Guinness World Records, "The fastest time to complete an Easy Sudoku puzzle is 2 min 8.53 sec by Thomas Snyder (USA) at BookExpo America, Washington DC, USA on 20 May 2006. The attempt was carried out under the auspices of the International Sudoku Organisation and the puzzles were created by Sudoku Grand Master Mike Mepham. Thomas Snyder is American champion and was the second-place finisher at the first World Sudoku Championships in Lucca, Italy in March 2006." Once again, there is obvious cheating occurring on the extreme level of Sudoku.
GWR confirms its results in a controlled environment, which solving a puzzle on one's phone (tablet) is not, clearly. But just because GWR wasn't around to record / confirm the results of those in our top "charts" does not prove that there is cheating occurring.
Argle wrote:And again, what are the administrators going to do about it?
We've addressed the issue of cheating on a number of occasions. Feel free to browse through this forum to read our comments. Our position hasn't changed. I'll add that if you are able to point out a time on our leaderboards that you are able to prove is a result of cheating, we'll be happy to take it down. Until such time we are going with the mantra of "innocent until proven guilty".
Now let me close with a question of my own: why would anyone go into trouble of cheating in this game, when there is nothing to be gained by it? (the top lists are on 24 hour rolling basis, so whatever fame there is to be gained is fleeting)
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gold wrote:where can I find the timings of my past played games on the mobile in the site
http://genina.com/apps/sudoku/stats.jsf - look under the last tab.
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Your purchases are tied to your Google account. If you are using the same account you used to make the purchase originally, you will be recognized. If you are sure that's the case and you are still not recognized you'd probably need to contact Google.
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Nothing is being extracted. Please read the app description on Google Play for a detailed description of what each of the required permissions is for.
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Hello. We need your help in identifying where the ad is coming from. Would you be able to provide some additional information and help us troubleshoot? If so, please write to debug@genina.com
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Right, you need to long-press it. Have you tried that? (While in game?)
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Why is that not an option for you?
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It depends on your device, but usually it is accessible by long-pressing the "Recent Tasks" button found next to the "Home" button. We are working on a better way of accessing it, so please bear with us.
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The premium is ad-free. That's the only difference.
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Thanks, we'll look into this and will address what we find with the next release.
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Thanks for reporting this. To help us troubleshoot, please provide this information:
What device are you on?
What is the OS version you are running?
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rdwells wrote:
Check out R1C3. If that's a 6, then there are 4 squares in a rectangle (R2C3, R2C5, R3C3, and R3C5) that are all either 1 or 4; this would lead to multiple solutions, which would mean the puzzle is invalid. So R1C3 must be 4.
If you keep solving the puzzle with this assumption, i.e. that R1C3 is 6, you will come to a point where you'll realize that, in fact, no solution exists, i.e. putting a 6 in R1C3 is wrong. So, no, this will not lead to multiple solutions, but rather to no solution at all.
rdwells wrote:
Question for others: Is the assumption that there are no multiple solutions valid? It should be true of any well-created puzzle, and I use often it in situations like the one here, but it just kinda feels wrong.
This assumption is valid, however, this approach is still wrong.
Now about solving this particular puzzle, notice that R7C2 and R8C9 will always have the same value (either a 1 or a 9) that is enforced by R7C8, however, that value cannot be 1 because that would prevent both R5C2 and R5C9 from having a 1. Therefore, the value in both R7C2 and R8C9 must be a 9.
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